L.E.D. Flashers Woes; Mystery disconnect harness

[workmeistr]

O.K., old thread, but,
I mounted two 6 ohm load resistors, one on each side in the back.
On one lead, I tapped into the power of the turn signal wire at the base of the light cluster wire loom, to the other resistor lead, I tapped into the ground wire, further up before the ground wire attaches to the turn signal bulb base. I thought that the load only needed to be on the flashing turn signal, so that is why I walked up a wire to put the load on the common negative wire past the splices for the other two lights. This may have been flawed reasoning, though, as:

I still have hyper-flash on normal turn signal mode, however, I have a normal flash speed on Hazard mode (I guess the 2 x 6 ohms is enough resistance to have the blinker module flash normally).

So, what did I do wrong? Others had suggested that 2 x 6 ohm in the back only would provide enough resistance for normal turn signal flash speed. I guess I'll have to run resistors in the fronts, unless someone thinks that I should have tapped the ground down at the base of the common ground wire before all three lights. Though, I can't fathom why that would make any difference, but I am a novice wirer..er..er. Thanks for any suggestions.

[etlsport]

i've never installed the resistors before... but I would think that your resistor should be just an interruption of the power wire, not even touching the ground. the current will choose the path of least resistance, so it will just go around the resistor and through the LED as it would have if the resistor wasnt there at all...

[etlsport]

did some more research.. looking at moncha's review of the flashers and the website. it seems that a 6ohm resistor will only make up for one of our turn signals going to LED.. a 3 ohm resistor will account for 2 turn signals (front and rear).. so if you put a 3 ohm resistor in the place of the 6 you have there... should take care of your problems

the capacitor that controls the rate of flash of the turn signals is based on the current through the circuit. the current through leds is much lower than through the regular bulb. a lower current with the same voltage gives a higher resistance. to lower that resistance you add a new resistor in parallel with the lights.. resistors in parallel effectively lower resistance.. so by decreasing your resistance you increase the current through the circuit.. causing the capacitor to discharge less frequently... i think